const String [] operator

[dynamicsr@juno.com (Dynamics Research)]

I get a warning from the compiler from the following code.

String Increment(const String& old)
  {
  if(old[2] < 'a')
    {
    // some processing
    }		
  }

The warning is 'non-const ... operator[] called for constant object. I
think I understand that the compiler is complaining that [] could change
the passed string 'old' which would be illegal since 'old' is const. The
compile apparently doesn't care that my code doesn't attempt to change
'old'

What syntax can I use to make the comparison I want and still have the
'old' passed as a const but not get a warning?


Thom Burnett

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